0

Is there a software where people can chat individually and in a group, but without a center server, and all communication transferred via users' email?

For example, when a user talks with another user, what actually happens is that an email was sent. When a user joins a chatroom, the mechanism is that everyone else in this chatroom receives an email notifying that a new user is in.

I guess someone should have built such a software, since it requires no special servers, but makes use of the existing ones for email.

(Maybe plugins for digsby & pidgin?)

I wish it open-source and HTML & JS based (c.f. Electron), so that it is easier to be ported into various platforms.

3
  • 1
    Not sure how well it fits your bill, but did you take a look at Der E-Mail-Messenger - Delta Chat? You didn't specify what OS it must run on (DeltaChat supports Android, iOS/macOS, Linux & Windows, so you should be covered concerning that) or how much it may cost (DC is free/libre & open source).
    – Izzy
    Apr 26 at 17:13
  • @Izzy That's exactly what I am looking for, thank you!! Will you turn it into an answer? Apr 27 at 4:15
  • 1
    Glad to read! And done: answer below with a few additional details. Enjoy! \o/
    – Izzy
    Apr 27 at 7:16
1

Delta Chat seems to be what you are after. It uses plain IMAP as back-end (so all that's needed is an EMail account you already have, and Delta will have its own mail folder in there).

  • but without a center server: no central server, it works via each user's mailbox
  • all communication transferred via users' email: exactly ;)
  • what actually happens is that an email was sent: that's what's happening in the background – though at the front-end it looks like a chat client
  • open-source: sources can be found at Github

Delta Chat is available cross-platform, with clients for Android, iOS/macOS, Linux & Windows.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.